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.8x=2.5x^2
We move all terms to the left:
.8x-(2.5x^2)=0
We get rid of parentheses
-2.5x^2+.8x=0
a = -2.5; b = .8; c = 0;
Δ = b2-4ac
Δ = .82-4·(-2.5)·0
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.8)-\sqrt{0.64}}{2*-2.5}=\frac{-0.8-\sqrt{0.64}}{-5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.8)+\sqrt{0.64}}{2*-2.5}=\frac{-0.8+\sqrt{0.64}}{-5} $
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